(x^2+5x-6)/(x^2-4)

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Solution for (x^2+5x-6)/(x^2-4) equation: 


D( x )

x^2-4 = 0

x^2-4 = 0

x^2-4 = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in (-oo:-2) U (-2:2) U (2:+oo)

(x^2+5*x-6)/(x^2-4) = 0

x^2+5*x-6 = 0

x^2+5*x-6 = 0

DELTA = 5^2-(-6*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-5)/(1*2) or x = (-49^(1/2)-5)/(1*2)

x = 1 or x = -6

(x+6)*(x-1) = 0

((x+6)*(x-1))/(x^2-4) = 0

( x+6 )

x+6 = 0 // - 6

x = -6

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -6, 1 }

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